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Factorise : (lm + l) + m + 1
Given: $ (lm+l)+m+1$
To do: Factorise the given expression
Solution:
$ (lm+l)+m+1$
= $ l(m+1) + m + 1 $
We can take m+1 as common
= $ (m+1)(l+1) $
So $ (m+1) , (l+1) $ are the two factors
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