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Factorise $16x^{4}-4x^{2}+4x-1 ?$
Given: The polynomial $16x^{4}-4x^{2}+4x-1$
To do: To factorise the given polynomial.
Solution:
$16x^4–(4x^2–4x+1)$
$=16x^4-(2x-1)^2$
Now using $a^2-b^2=(a+b)(a-b)$
$(4 x^2)^2-(2x-1)^2$
$=(4x^2–2x+1)(4x^2+2x-1)$
Updated on: 10-Oct-2022
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