Factorise $ 16(2 p-3 q)^{2}-4(2 p-3 q) $.

Given:

\( 16(2 p-3 q)^{2}-4(2 p-3 q) \).

To do:

We have to factorise the given expression.

Solution:

$16(2 p-3 q)^{2}-4(2 p-3 q)=4(2p-3q)[4(2p-3q)-1]$   (Taking $4(2p-3q)$ common) $=4(2p-3q)(8p-12q-1)$ Therefore,

Factorisation of $16(2 p-3 q)^{2}-4(2 p-3 q)$ is $4(2p-3q)(8p-12q-1)$.

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Updated on: 10-Oct-2022

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