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Express each of the following rational numbers with a negative exponent:
(i) $ \left(\frac{1}{4}\right)^{3} $
(ii) $ 3^{5} $
(iii) $ \left(\frac{3}{5}\right)^{4} $
(iv) $\left\{\left(\frac{3}{2}\right)^{4}\right\}^{-3} $
(v) $ \left\{\left(\frac{7}{3}\right)^{4}\right\}^{-3} $
To do:
We have to express the given rational numbers with negative exponents.
Solution:
We know that,
$\frac{1}{a^m}=a^{-m}$
$a^{m}=(\frac{1}{a})^{-m}$
$(\frac{a}{b})^m=(\frac{b}{a})^{-m}$
Therefore,
(i) $(\frac{1}{4})^{3}=(\frac{4}{1})^{-3}$
$=(4)^{-3}$
(ii) $(3)^{5}=(\frac{1}{3})^{-5}$
(iii) $(\frac{3}{5})^4=(\frac{5}{3})^{-4}$
(iv) $((\frac{3}{2})^{4})^{-3}=(\frac{3}{2})^{4\times(-3)}$
$=(\frac{3}{2})^{-12}$
(v) $((\frac{7}{3})^{4})^{-3}=(\frac{7}{3})^{4\times(-3)}$
$=(\frac{7}{3})^{-12}$
(v) $((\frac{7}{3})^{4})^{-3}=(\frac{7}{3})^{4\times(-3)}$
$=(\frac{7}{3})^{-12}$
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