Examine each of the following statements and comment: If a die is thrown once, there are two possible outcomes -an odd number or an even number. Therefore, the probability of obtaining an odd number is $ \frac{1}{2} $ and the probability of obtaining an even number is $ \frac{1}{2} . $
Given:
If a die is thrown once, there are two possible outcomes -an odd number or an even number. Therefore, the probability of obtaining an odd number is \( \frac{1}{2} \) and the probability of obtaining an even number is \( \frac{1}{2} . \)
To do:
We have to find whether the given statement is true or false.
Solution:
When a die is thrown, the total possible outcomes are 1, 2, 3, 4, 5 and 6.
This implies,
The total number of possible outcomes $n=6$.
We know that,
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability of getting an odd number $=\frac{3}{6}=\frac{1}{2}$
Probability of getting an even number $=\frac{3}{6}=\frac{1}{2}$
Therefore, the given statement is true.
Related Articles
- Which of the following arguments are correct and which are not correct? Give reasons for your answer.If a die is thrown, there are two possible outcomes- an odd number or an even number. Therefore, the probability of getting an odd number is $\frac{1}{2}$.
- Which of the following arguments are correct and which are not correct? Give reasons for your answer.(i) If two coins are tossed simultaneously there are three possible outcomes- two heads, two tails or one of each. Therefore, for each of these outcomes, the probability is $\frac{1}{3}$.(ii) If a die is thrown, there are two possible outcomes- an odd number or an even number. Therefore, the probability of getting an odd number is $\frac{1}{2}$.
- A die is thrown once. Find the probability of getting an odd number.
- A die is thrown. Find the probability of getting an even prime number.
- The probability of getting an even number, when a dice is thrown once, is:$( A)\frac{1}{2}$$( B)\frac{1}{3}$$( C)\frac{1}{6}$$( D)\frac{5}{6}$
- A die is thrown once. Find the probability of getting (i) a prime number; (ii) a number lying between 2 and 6; (iii) an odd number
- When a dice is thrown once, find the probability of getting an even number.
- Every even number is followed by an odd number and every odd number is followed by an even number. What is the meaning ?
- A dice is thrown. Find the probability of getting an even number.
- Examine each of the following statements and comment: If two coins are tossed at the same time, there are 3 possible outcomes - two heads, two tails, or one of each. Therefore, for each outcome, the probability of occurrence is \( \frac{1}{3}. \)
- If two different dice are rolled together, the probability of getting an even number on both dice, is: $ (A)\ \frac{1}{36}$ $( B) \ \frac{1}{2}$ $( C) \ \frac{1}{6}$ $ ( D) \ \frac{1}{4} \ $
- State whether the following statements are True or False:(a) The sum of three odd numbers is even.(b) The sum of two odd numbers and one even number is even.(c) The product of three odd numbers is odd.(d) If an even number is divided by 2, the quotient is always odd.(e) All prime numbers are odd.(f) Prime numbers do not have any factors.(g) Sum of two prime numbers is always even.(h) 2 is the only even prime number.(i) All even numbers are composite numbers.(j) The product of two even numbers is always even.
- A black die and a white die are thrown at the same time. Write all the possible outcomes. What is the probability that of obtaining the same number on both dice?
- A die is thrown once. Find the probability of getting a number lying between 2 and 6.
- Construct an NFA accepting strings with an even number of 0s or an odd number of 1s
Kickstart Your Career
Get certified by completing the course
Get Started