Examine each of the following statements and comment: If a die is thrown once, there are two possible outcomes -an odd number or an even number. Therefore, the probability of obtaining an odd number is $ \frac{1}{2} $ and the probability of obtaining an even number is $ \frac{1}{2} . $


Given:

If a die is thrown once, there are two possible outcomes -an odd number or an even number. Therefore, the probability of obtaining an odd number is \( \frac{1}{2} \) and the probability of obtaining an even number is \( \frac{1}{2} . \)

To do:

We have to find whether the given statement is true or false.

Solution:

When a die is thrown, the total possible outcomes are 1, 2, 3, 4, 5 and 6.

This implies,

The total number of possible outcomes $n=6$.

We know that,

Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$

Therefore,

Probability of getting an odd number $=\frac{3}{6}=\frac{1}{2}$

Probability of getting an even number $=\frac{3}{6}=\frac{1}{2}$

Therefore, the given statement is true.

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Updated on: 10-Oct-2022

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