Evaluate:$ (0.2)^{3}-(0.3)^{3}+(0.1)^{3} $

Given: 

\( (0.2)^{3}-(0.3)^{3}+(0.1)^{3} \)

To do: 

We have to evaluate the given expression.

Solution: 

We know that,

If $x+y+z=0$, then $x^{3}+y^{3}+z^{3}=3 x y z$.

Let $a=0.2, b=-0.3$ and $c=0.1$

$a+b+c=0.2-0.3+0.1$

$=0$

This implies,

$a^{3}+b^{3}+c^{3}=3 a b c$

$(0.2)^{3}-(0.3)^{3}+(0.1)^{3}=3 \times (0.2)\times(-0.3)\times(0.1)$

$=-3 \times 0.006$

$=-0.018$

Hence, $(0.2)^{3}-(0.3)^{3}+(0.1)^{3}=-0.018$.

Tutorialspoint

Updated on: 10-Oct-2022

233 Views

Kickstart Your Career

Get certified by completing the course

Get Started