Evaluate:$ \frac{3}{7}+\frac{-4}{9}+\frac{-11}{7}+\frac{7}{9} $

Given:

\( \frac{3}{7}+\frac{-4}{9}+\frac{-11}{7}+\frac{7}{9} \)
To do:

We have to evaluate \( \frac{3}{7}+\frac{-4}{9}+\frac{-11}{7}+\frac{7}{9} \).
Solution:

$\frac{3}{7}+\frac{-4}{9}+\frac{-11}{7}+\frac{7}{9}=\frac{3+(-11)}{7}+\frac{-4+7}{9}$

$=\frac{-8}{7}+\frac{3}{9}$
$=\frac{-8\times9+3\times7}{63}$     (LCM of 7 and 9 is 63)
 $=\frac{-72+21}{63}$

$=\frac{-51}{63}$

$=\frac{-17}{21}$

Therefore,

$\frac{3}{7}+\frac{-4}{9}+\frac{-11}{7}+\frac{7}{9}=\frac{-17}{21}$.

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Updated on: 10-Oct-2022

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