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Evaluate $ \frac{2}{3}+0 . \overline{11} $.
Given :
\( \frac{2}{3}+0 . \overline{11} \).
To do :
We have to evaluate \( \frac{2}{3}+0 . \overline{11} \).
Solution :
$0. \overline{11}$
Let $x = 0.1111....$
Multiply both sides by 100.
$100x = 100(0.1111....)$
$100x = 11.1111.....$
Therefore,
$100x-x = 11.1111.... - 0.1111.....$
$99x = 11$
$x = \frac{11}{99}=\frac{1}{9}$
Therefore,
$\frac{2}{3}+0 . \overline{11}=\frac{2}{3}+\frac{1}{9}$
$=\frac{2\times3+1}{9}$
$=\frac{6+1}{9}$
$=\frac{7}{9}$
Hence, \( \frac{2}{3}+0 . \overline{11}=\frac{7}{9} \).
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