Evaluate each of the following using identities:$(a - 0.1) (a + 0.1)$

Given:

$(a - 0.1) (a + 0.1)$

To do:

We have to evaluate the given expression using a suitable identity.

Solution:

We know that,

$(a+b)^2=a^2+b^2+2ab$

$(a-b)^2=a^2+b^2-2ab$

$(a+b)(a-b)=a^2-b^2$
Therefore,

$(a-0.1)(a+0.1)=(a)^{2}-(0.1)^{2}$

$=a^{2}-0.01$

Hence, $(a-0.1)(a+0.1)=a^{2}-0.01$.

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Updated on: 10-Oct-2022

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