Evaluate each of the following using identities:$(1.5.x^2 - 0.3y^2) (1.5x^2 + 0.3y^2)$

Given:

$(1.5.x^2 - 0.3y^2) (1.5x^2 + 0.3y^2)$

To do:

We have to evaluate the given expression using a suitable identity.

Solution:

We know that,

$(a+b)^2=a^2+b^2+2ab$

$(a-b)^2=a^2+b^2-2ab$

$(a+b)(a-b)=a^2-b^2$
Therefore,

$(1.5 x^{2}-0.3 y^{2})(1.5 x^{2}+0.3 y^{2})=(1.5 x^{2})^{2}-(0.3 y^{2})^{2}$

$=2.25 x^{4}-0.09 y^{4}$

Hence, $(1.5 x^{2}-0.3 y^{2})(1.5 x^{2}+0.3 y^{2})=2.25 x^{4}-0.09 y^{4}$.

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Updated on: 10-Oct-2022

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