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Evaluate $ \cos 240^{\circ} $.
Given:
$cos\ 240^o$.
To do:
We have to evaluate $cos\ 240^o$.
Solution:
We know that,
$cos\ (180+x)=-cos\ x$ and
$cos\ 60^o=\frac{1}{2}$
Therefore,
$cos\ 240^o=cos\ (180+60)^o$
$=-cos\ 60^o$
$=-\frac{1}{2}$
Therefore, $cos\ 240^o=-\frac{1}{2}$.
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