Draw a right triangle $\vartriangle ABC$ is which $AB\ =\ 6\ cm,\ BC\ =\ 8\ cm$ and $\angle B\ =\ 90^{o}$.Draw BD perpendicular from B on AC and draw a circle passing through the points B, C And D. Construct tangents from A to this circle.
Given: $AB=6\ cm,\ BC=8\ cm$ and $\angle B=90^{o}$
To do: To draw the right triangle ABC. To .Draw BD perpendicular from B on AC and draw a circle passing through the points B, C And D.
To Construct tangents from A to this circle.
Solution:
Follow the given steps to construct the figure.
Step 1. Draw a line BC of 8 cm length
Step 2. Draw BX perpendicular to BC.
Step 3. Mark an arc at the distance of 6 cm on BX, Mark it as A .
Step 4. Join A and C. Thus, ABC is the required triangle.
Step 5. With B as the center, draw an arc on AC.
Step 6. Draw the bisector of this arc and join it with. Thus, BD is perpendicular
Step 7. Now, draw the perpendicular to AC bisector of BD and CD. Take the point of intersection as O.
Step 8. With O as the center and OB as the radius, draw a circle passing through points B, C and D.
Step 9. Join A and O and bisect it. Let P be the midpoint of AO .
Step 10. Taking P as the center and PO as its radius, draw a circle which will intersect the circle at point B and G. Join A and G.
Here, AB and AG are the required tangents to the circle from A.
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