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Draw a linear pair of angles. Bisect each of the two angles. Verify that the two bisecting rays are perpendicular to each other.
To do:
We have to draw a linear pair of angles, bisect each of the two angles and verify that the two bisecting rays are perpendicular to each other.
Solution:
Steps of construction:
(i) Draw a linear pair, $\angle DCA$ and $\angle DCB$.
(ii) Draw the bisectors of $\angle DCA$ and $\angle DCB$ forming $\angle ECF$ on measuring, we get, $\angle ECF = 90^o$.
Verification:
$\angle DCA +\angle DCB = 180^o$
$\frac{1}{2}\angle ∠DCA + \frac{1}{2}\angle DCB = 180^o \times \frac{1}{2}$
$= 90^o$
Therefore,
$\angle ECF = 90^o$
This implies,
$EC$ and $FC$ are perpendicular to each other.
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