Draw a line segment $ A B=5.5 \mathrm{cm} $. Find a point $ P $ on it such that $ \overline{A P}=\frac{2}{3} \overline{P B} $.

Academic Mathematics NCERT Class 8

Given : \( A B=5.5 \mathrm{cm} \). \( \overline{A P}=\frac{2}{3} \overline{P B} \).

To find: point \( P \) on AB

Solution:

Let P be a point such that AP=$\frac{2}{3}$PB

=>AP+PB=AB

$\frac{2}{3}$ PB+PB=5.5

$\frac{5}{3}$PB=5.5

PB=3.3cm

AP=2.2cm

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Updated on: 10-Oct-2022

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