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Divide the sum of 3/2 and 7/8 by the product of 2/5 and 2.
To find: We have to find the value when the sum of 3/2 and 7/8 by the product of 2/5 and 2.
Solution:
$sum\ of\ \frac{3}{2} \ and\ \frac{7}{8} \ =\ \frac{3}{2} \ +\ \frac{7}{8} \ =\ \frac{12}{8} \ +\ \frac{7}{8} \ =\ \frac{19}{8}$
$Now,\ product\ of\ \frac{2}{5} \ and\ 2\ is\ \frac{4}{5}$
$Therefore,\ When\ we\ divide\ \frac{19}{8} \ and\ \frac{4}{5} ,\ we\ get\ the\ following$
$\Longrightarrow \ \frac{\frac{19}{8}}{\frac{4}{5}} \ =\ \frac{19}{8} \ \times \ \frac{5}{4} \ =\ \frac{95}{32}$
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