Divide the following:$9^3 + 18^2 - 9$ by $3l+3$.

Given :

The given terms are $9^3 + 18^2 - 9$ and $3l+3$.

To do :

We have to divide the given expressions.

Solution :

Dividend $=9^3 + 18^2 - 9$

Divisor $= 3l+3$

$3l+3)9^3 + 18^2 - 9( 3l^2+3l-3$

         $9l^3+9l^2$

-------------------                                       $ \frac{9l^3}{3l} = 3^2$

                  $9l^2-9$

                  $9l^2+9l$

-----------------------                                   $\frac{9l^2}{3l} = 3l$

                        $ -9l-9$

                         $-9l-9$                                         $\frac{-9l}{3l} = -3$

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                              0

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The quotient is $3l^2+3l-3$ and the remainder is 0.

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Updated on: 10-Oct-2022

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