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Divide:
$y^{4}\ +\ y^{2}$ by $y^{2}\ -\ 2$
Given: $y^{4}\ +\ y^{2}$ and $y^{2}\ -\ 2$.
To do: Here we have to divide $y^{4}\ +\ y^{2}$ by $y^{2}\ -\ 2$.
Solution:
Dividing $y^{4}\ +\ y^{2}$ by $y^{2}\ -\ 2$:
So, $y^{4}\ +\ y^{2}\ =\ (y^{2}\ -\ 2)(y^{2}\ +\ 3)\ +\ 6$.
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