Divide (i) n² - 2n + 1 by n - 1

Given: n² - 2n + 1 by  n - 1

To find: We have to divide n2 - 2n + 1 by n - 1

Solution:

Factorizing numerator n² - 2n + 1 by using the identity

x² - 2xy + y² = (x - y)²

n² - 2n + 1 = n² - 2$\times$n$\times$1 + 1² = (n - 1)²= (n -1)(n - 1)

$\left(\frac{n^{2} \ -\ 2n\ +\ 1}{n-1}\right)$ = $\frac{( n\ -1)( \ n\ -\ 1)}{n-1}$ = n - 1 

So$\left(\frac{n^{2} \ -\ 2n\ +\ 1}{n-1}\right)$ = n - 1  

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Updated on: 10-Oct-2022

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