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Divide
$2x^3-5x^2+8x-5 \ by \ 2x^2-3x+5$
Solution:
$2 x ^2- 5 x ^2+ 8 x - 5 \ divided\ by \ 2 x ^2- 3 x + 5$
  $2 x^2 - 3 x + 5$ ) $2 x^3 - 5 x^2 + 8 x - 5( x - 1$
$2 x ^3 - 3 x^2 + 5 x$
(-) (+) (-)
____________________
$- 2 x^2 + 3 x - 5$
$- 2 x^2 + 3 x - 5$
(+) (-) (+)
____________________
0
Therefore when $2 x^3 - 5 x^2 + 8 x - 5 \ is \ divided \ by \ 2 x^2- 3 x + 5$
Quotient - x - 1
Remainder - 0