Derive the following equation of motion: $v^2 = u^2 + 2as$, where the symbols have their usual meanings.

We know the first equation of motion $v=u+at$

 While $u\rightarrow$ Initial velocity

$v\rightarrow$ Final velocity

$a\rightarrow$ Acceleration

$t\rightarrow$ Time taken

We know the displacement $s=(\frac{u+v}{2})t$

And from first equation of motion Time $t=(\frac{v-u}{a})$

Therefore, Displacement $s=(\frac{v+u}{2})(\frac{v-u}{a})$

Or $s=\frac{v^2-u^2}{2a}$

Or $v^2-u^2=2as$

Or $v^2=u^2+2as$

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

65 Views

Kickstart Your Career

Get certified by completing the course

Get Started