Construct the angles of the following measurements:
$75^o$

To do:

We have to construct $75^o$.

Solution:

Steps of construction:

(a) Draw a line segment $BC$.

(b) With centre $B$ and a suitable radius, draw an arc meeting $BC$ at $E$.

(c) Cut off arc $EF = FG$ from $E$.

(d) Bisect the arc $FG$ at $K$ and join $BK$ so that $\angle KBC = 90^o$.

Bisect arc $HF$ at $L$ and join $BL$ and produce it to $

Therefore,

$\angle ABC = 75^o$.

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Updated on: 10-Oct-2022

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