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Complete the entries in the third column of the table.
"
To do:
We have to complete the entries in the third column of the given table.
Solutions:
(a) $10y = 80$
If $y = 10$ then $10y=10(10)=100$
$y=10$ is not a solution for the equation $10y = 80$
Therefore, the equation is not satisfied.
(b) $10y = 80$
If $y = 8$ then $10y=10(8)=80$
$y=8$ is a solution for the equation $10y = 80$
Therefore, the equation is satisfied.
(c) $10y = 50$
If $y = 5$ then $10y=10(5)=50$
$y=5$ is not a solution for the equation $10y = 80$
Therefore, the equation is not satisfied.
(d) $4l = 20$
If $l = 20$ then $4l=4(20)=80$
$l=20$ is not a solution for the equation $4l = 20$
Therefore, the equation is not satisfied.
(e) $4l = 20$
If $l = 20$ then $4l=4(20)=80$
$l=20$ is a solution for the equation $4l = 80$
Therefore, the equation is satisfied.
(f) $4l = 20$
If $l = 5$ then $4l=4(5)=20$
$l=5$ is a solution for the equation $4l = 20$
Therefore, the equation is satisfied.
(g) $b + 5 = 9$
If $b = 5$ then $b+5=5+5=10$
$b=5$ is not a solution for the equation $b+5 = 9$
Therefore, the equation is not satisfied.
(h) $b + 5 = 9$
If $b = 9$ then $b+5=9+5=14$
$b=9$ is not a solution for the equation $b+5 = 9$
Therefore, the equation is not satisfied.
(i) $b + 5 = 9$
If $b =4$ then $b+5=4+5=9$
$b=4$ is a solution for the equation $b+5 = 9$
Therefore, the equation is satisfied.
(j) $h - 8 = 5$
If $h =13$ then $h-8=13-8=5$
$h=13$ is a solution for the equation $h-8= 5$
Therefore, the equation is satisfied.
(k) $h - 8 = 5$
If $h = 8$ then $h-8=8-8=0$
$h=8$ is not a solution for the equation $h-8 = 5$
Therefore, the equation is not satisfied.
(l) $h - 8 = 5$
If $h = 0$ then $h-8=0-8=-8$
$h=0$ is not a solution for the equation $h-8 = 5$
Therefore, the equation is not satisfied.
(m) $p + 3 = 1$
If $p = 3$ then $p+3=3+3=6$
$p=3$ is not a solution for the equation $p+3 = 6$
Therefore, the equation is not satisfied.
(n) $p + 3 = 1$
If $p = 1$ then $p+3=1+3=4$
$p=1$ is not a solution for the equation $p+3 = 1$
Therefore, the equation is not satisfied.
(o) $p + 3 = 1$
If $p = 0$ then $p+3=0+3=3$
$p=0$ is not a solution for the equation $p+3 = 1$
Therefore, the equation is not satisfied.
(p) $p + 3 = 1$
If $p = -1$ then $p+3=-1+3=2$
$p=-1$ is not a solution for the equation $p+3 = 1$
Therefore, the equation is not satisfied.
(q) $p + 3 = 1$
If $p = -2$ then $p+3=-2+3=1$
$p=-2$ is not a solution for the equation $p+3 = 1$
Therefore, the equation is satisfied.
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