Calculate the molecular mass of ethanoic acid, CH3COOH.(Atomic masses : C = 12 u; H = 1 u; O = 16 u)


The molecular mass of ethanoic acid (CH3COOH)
= 1xC + 3xH + 1xC + 2xO +1xH
= 12+3+12+32+1
= 60u

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Updated on: 10-Oct-2022

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