Calculate the density of an object of volume $3\ m^3$ and mass $9\ kg$. State whether this object will float or sink in water. Give reason for your answer.

Here given, Volume of the object $V=3\ m^3$

Mass of the object $m=9\ kg$

Therefore, density $=\frac{mass(m)}{volume(V)}$

$=\frac{9\ kg}{3\ m^3}$

$=3\ kg/m^3$

Therefore, the density of the object is $3\ kg/m^3$ which is less than the density of the water$1000\ kg/m^3$. So the object will float in the water.

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Updated on: 10-Oct-2022

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