Calculate the acceleration of an object having the initial velocity 4m/s and after moving 4 meters comes to rest in 2 seconds?

Given,

Initial Velocity, u = 4 m/s

Distance, s = 4 m 

Time, t = 2 s

To find = Acceleration, a

Solution-

From the 2nd law of motion, we know that,

$s=ut+\frac{1}{2}a{t}^{2}$

Substituting the given values we get-

$4=4\times 2+\frac{1}{2}\times a\times (2{)}^{2}$

$4=8+\frac{1}{2}\times 4\times a$

$4=8+1\times 2\times a$

$4=8+2a$

$2a=4-8$
$a=\frac{-4}{2}$
$a=-2m/{s}^{2}$

Therefore, the acceleration of the object will be -2m/s².

Here, the minus sign indicates that acceleration is to the left, which means retardation or deceleration or the negativity to speed.

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

73 Views

Kickstart Your Career

Get certified by completing the course

Get Started