Solve the following:$\frac{1.98 \times 1.98-1.02 \times 1.02}{0.96} $

Given: $\frac{1.98 \times 1.98-1.02 \times 1.02}{0.96} $

To do: Solve the following

Solution:

$\frac{1.98 \times 1.98-1.02 \times 1.02}{0.96} $

= $\frac{1.98^2 -1.2^2}{0.96}$

Using identity $a^2 - b^2 = (a+b)(a-b)$

= $\frac{(1.98+1.02)(1.98-1.02)}{0.96}$

= $\frac{3.00 \times 0.96}{0.96}$

=3

Therefore, the solution of the expression is 3

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Updated on: 10-Oct-2022

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