Simplify
a. $ 2 a+(3 a-b+a) $
b. $a+(4 a-a)+(7 a-a) $
с. $ 11 b-a+2(3 a-b)


Solution:

a)

$2a + (3a - b + a)$

= $2a + ( 4a - b)$

= $6a - b$

b)

$a + (4a -a) + (7a - a)$

= $a + 3a + 6a$

= $10a$


c)

$11b - a + 2(3a - b)$

$= 11b -a + 2\times3a -2\times b$

= $9b + 5a$

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Updated on: 10-Oct-2022

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