Calculate the number of molecules present in a drop of chloroform (CHCl3) weighing 0.0239 g.(Atomic mass : C = 12 u ; H = 1 u ; Cl = 35.5 u)
Mass of chloroform = 0.0239g
Molar mass of chloroform = (1 × 12) + (1 × 1) + (3 × 35.5) = 119.5g
Number of molecules in 119.5g of chloroform = 6.022 × 1023
Number of molecules in 1g of chloroform = 6.022 × 1023 / 119.5
Number of molecules in 0.0239g of chloroform = 0.0239 × 6.022 × 1023/119.5
Therefore, a drop of chloroform weighing 0.0239g has 1.2 × 1020 molecules.
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