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(a) What happens when propanoic acid is warmed with methanol in the presence of a few drops of concentrated sulphuric acid? Write equation of the reaction involved.(b) What change will you observe if you test soap solution with a litmus paper (red and blue)? Give reason for your observation.
(c) What is meant by denatured alcohol? What is the need to denature alcohol?
(a) When propanoic acid is warmed with methanol in the presence of a few drops of concentrated sulphuric acid, esterification takes place and an ester (methyl propanoate) is formed along with water.
The chemical equation for the reaction is given below:
$C_2H_5COOH + CH_3OH → C_2H_5COOCH_3 + H_2O$
(b) Soap is the salt of a strong base (sodium hydroxide) and a weak acid (carboxylic acid). Hence, its solution with water is also basic in nature. Therefore, it will turn red litmus paper blue and no change will be observed in blue litmus paper.
(c) Denatured alcohol is ethyl alcohol to which small amounts of poisonous substances like methanol and copper sulphate are added to make it unfit for consumption.
Ethyl alcohol is used for manufacturing various products in different industries. Therefore, the government supplies ethyl alcohol to the industries without charging production tax. Denatured alcohol is made to prevent the misuse of industrial alcohol for drinking purposes or black marketing.
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