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(a) Derive the relation between commercial unit of energy (kWh) and SI unit of energy (joule).
(b) A certain household consumes 650 units of electricity in a month. How much is this electricity in joules?
(a). Derivation of the relation between (kWh) and (Joule):
$1\ kWh=1\ kW\times 1\ hour$
$=1000\ Watt\times 60\times60\ seconds$
$=3.6\ 10^6\ Watt-seconds$
$=3.6\times10^6\ Joule$
Therefore, $1\ kWh$ is equal to $3.6\times10^6\ Joule$.
(b). Electricity used in household $=650\ units$
$=650\ kWh$ [commercial unit of power is $kWh$]
$=650\times3.6\times10^6\ Joule$
$=2340\times10^6\ Joule$
$=23.4\times10^7\ Joule$
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