At the end of the winter season, a shopkeeper earns a profit of rupees 100 by selling a shirt but incurred a loss of rupees 50 on selling a woolen jacket. At the end of the sale on one day, he incurred a loss of rupees 200 while he sold 10 Jacket. How many shirts did he sell on that day?

Given :

Profit earned by selling a shirt $= Rs. 100$

The loss incurred by selling a Woollen jacket $= Rs. 50$

Total loss incurred at the end of the day $= Rs. 200$

Number of jackets sold $= 10$

To find :

We have to find the number of jackets he sold on the day.

Solution :

Loss incurred by selling jackets $= Rs. 10 \times 50 = Rs. 500$

Let the number of shirts sold be p.

Profit earned by selling p shirts $= Rs. p \times 100 = Rs. 100p$.

Therefore,

$Rs. 500 - Rs. 100p = Rs. 200$

$100p = 500-200$

$100p = 300$

$p = \frac{300}{100}$

$p = 3$.

Therefore, the number of shirts sold on that day is 3.