At the end of the winter season, a shopkeeper earns a profit of rupees 100 by selling a shirt but incurred a loss of rupees 50 on selling a woolen jacket. At the end of the sale on one day, he incurred a loss of rupees 200 while he sold 10 Jacket. How many shirts did he sell on that day?
Given :
Profit earned by selling a shirt $= Rs. 100$
The loss incurred by selling a Woollen jacket $= Rs. 50$
Total loss incurred at the end of the day $= Rs. 200$
Number of jackets sold $= 10$
To find :
We have to find the number of jackets he sold on the day.
Solution :
Loss incurred by selling jackets $= Rs. 10 \times 50 = Rs. 500$
Let the number of shirts sold be p.
Profit earned by selling p shirts $= Rs. p \times 100 = Rs. 100p$.
Therefore,
$Rs. 500 - Rs. 100p = Rs. 200$
$100p = 500-200$
$100p = 300$
$p = \frac{300}{100}$
$p = 3$.
Therefore, the number of shirts sold on that day is 3.
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