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Arun completes two rounds of a circular track of radius $50m\ in\ 40s$. What will be the distance covered and the displacement at the end of $2\ min\ 40s$?
Given: Arun completes two rounds of a circular track of diameter 50m in 40 s.
To find: distance covered and the displacement at the end of 2 minutes 40 s
Solution:
The distance he travels in 40 sec is $2\times 2 \pi \times 50 = 200\pi$
Total time given is 2 min 40 sec = 160sec
= 40 $ \times $ 4
Therefore, he travels $4\times 2$ rounds.
Therefore the distance traveled = $4 \times 200\pi = 800\pi$.
Displacement is nothing but the distance between the final point and initial point.
At the end of 2 min and 40 sec, he would be exactly at the starting point.
Therefore, the displacement is 0
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