Arrange the numbers in descending order :
$\frac{4}{5}, \frac{2}{7}, \frac{5}{3}$

Given :

The given terms are $\frac{4}{5}, \frac{2}{7}, \frac{5}{3}$.

To do :

We have to arrange the given terms in descending order.

Solution : 

  

$\frac{4}{5}, \frac{2}{7}, \frac{5}{3}$.

To arrange the given numbers in descending order first we have to find the LCM of the denominators.

LCM of 5,7 and 3 $= 5\times7\times3 = 105$.

$\frac{4}{5} = \frac{4\times 21}{5 \times 21} = \frac{84}{105}$

$\frac{2}{7} = \frac{2\times 15}{7 \times 15} = \frac{30}{105}$

$\frac{5}{3} = \frac{5 \times 35}{3 \times 35} = \frac{175}{105}$

Comparing the numerators,

$30<84<175$

Therefore,

$\frac{175}{105} > \frac{84}{105} > \frac{30}{105}$

$\frac{5}{3} >\frac{4}{5} >\frac{2}{7}$

The given numbers in descending order is $\frac{5}{3} ,\frac{4}{5} ,\frac{2}{7}$