Arrange the numbers in descending order :
$\frac{4}{5}, \frac{2}{7}, \frac{5}{3}$
Given :
The given terms are $\frac{4}{5}, \frac{2}{7}, \frac{5}{3}$.
To do :
We have to arrange the given terms in descending order.
Solution :
$\frac{4}{5}, \frac{2}{7}, \frac{5}{3}$.
To arrange the given numbers in descending order first we have to find the LCM of the denominators.
LCM of 5,7 and 3 $= 5\times7\times3 = 105$.
$\frac{4}{5} = \frac{4\times 21}{5 \times 21} = \frac{84}{105}$
$\frac{2}{7} = \frac{2\times 15}{7 \times 15} = \frac{30}{105}$
$\frac{5}{3} = \frac{5 \times 35}{3 \times 35} = \frac{175}{105}$
Comparing the numerators,
$30<84<175$
Therefore,
$\frac{175}{105} > \frac{84}{105} > \frac{30}{105}$
$\frac{5}{3} >\frac{4}{5} >\frac{2}{7}$
The given numbers in descending order is $\frac{5}{3} ,\frac{4}{5} ,\frac{2}{7}$
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