Arrange the following rational numbers in the descending order:$\frac{-3}{10},\ \frac{7}{-15},\ \frac{-11}{20},\ \frac{17}{-30}$.
Given: Rational numbers: $\frac{-3}{10},\ \frac{7}{-15},\ \frac{-11}{20},\ \frac{17}{-30}$.
To do: To arrange the given rational numbers in the descending order.
Solution:
Given rational numbers are: $\frac{-3}{10},\ \frac{7}{-15},\ \frac{-11}{20},\ \frac{17}{-30}$.
L.C.M. of the the nominators$=60$
Therefore, $\frac{-3}{10}=\frac{-3\times6}{10\times6}=\frac{-18}{60}$
$\frac{7}{-15}=\frac{7\times4}{-15\times4}=\frac{28}{-60}$
$\frac{-11}{20}=\frac{-11\times3}{20\times3}=\frac{-33}{60}$
$\frac{17}{-30}=\frac{17\times2}{-30\times2}=\frac{34}{-60}$
On arranging the newly obtained rational numbers in descending order:
$\frac{-18}{60}>\frac{28}{-60}>\frac{-33}{60}>\frac{34}{-60}$
Or
$\frac{-3}{10}>\frac{7}{-15}>\frac{-11}{20}>\frac{17}{-30}$.
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