An organic compound A (molecular formula C2H4O2) reacts with Na metal to form a compound B and evolves a gas which burns with a pop sound. Compound A on treatment with an alcohol C in the presence of a little of concentrated sulphuric acid forms a sweet-smelling compound D (molecular formula C3H6O2). Compound D on treatment with NaOH solution gives back B and C. Identify A, B, C and D.
The organic compound, A is ethanoic acid (CH3COOH), as it evolves hydrogen with a pop sound on reacting with sodium.
When (A) ethanoic acid reacts with sodium, sodium ethanoate (CH3COONa) is formed. Therefore, B is sodium ethanoate.
The alcohol, C, is methanol (CH3OH) which is treated with ethanoic acid in the presence of concentrated sulphuric acid to form a compound D.
The sweet-smelling compound D (ester) is methyl ethanoate (CH3COOCH3).
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