An object travels $20\ m$ in $5\ s$ and then another $40\ m$ in $5\ s$. What is the average speed of the object?
  1. $6\ m/s$
  2. $0\ m/s$
  3. $12\ m/s$
  4. $2\ m/s$


Here, total distance traveled $=20\ m+40\ m=60\ m$

Total time $t=5\ s+5\ s=10\ s$

Therefore, average speed $=\frac{total\ distance}{total\

 time}$

$=\frac{60\ m}{10\ s}$

$=6\ m/s$

Therefore, option a). is correct.

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Updated on: 10-Oct-2022

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