An object travels $20\ m$ in $2s$ and then another $16\ m$ in $2s$. What is the average speed of the object?

For the first part of the journey:

Distance $d_1=20\ m$

Time $t_1=2\ s$

For the second part of the journey:

Distance $d_2=16\ m$

Time $t_2=2\ s$

Therefore, total distance $d=d_1+d_2=20\ m+16\ m=36\ m$

Total time $t=t_1+t_2=2\ s+2\ s=4\ s$

The average speed of the object $=\frac{Total\ distance}{Total\ time}$

$=\frac{36\ m}{4\ s}$

$=9\ m/s$

Therefore, the average speed of the object is $9\ m/s$.

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Updated on: 10-Oct-2022

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