An insect crawls up $5\ cm$ every second on a $60\ cm$ vertical rod and falls down $2\ cm$ over the next seconds. How many seconds will it take to climb the rod?
Given: An insect crawls up $5\ cm$ every second on a $60\ cm$ vertical rod and falls down $2\ cm$ over the next seconds.
To do: To find the time taken to to climb the rod.
Solution:
As given, he insect goes up by $5\ cm$ in a seconds
Then, it comes down by $2\ cm$ in next one seconds
$\therefore$ Distance travelled by insect in $2\ seconds=5-2=3\ cm$.
Therefore, The insect travels $3\ cm$ in two seconds
$\therefore$ Time taken to travel $60\ cm=( \frac{60}{3})\times2\ sec$
$=20\times2$
$=40\ seconds$
Therefore, The insect will take $40\ seconds$ to climb the rods.
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