An experiment was conducted using 4 litres of water and ice made from 3 litres of water. The conditions were set in such a way that the water evaporated at a constant rate of $\frac{7}{4} l/h$ and ice melted at a constant rate producing $\frac{3}{2}$ litres of water per hour. How many hours will it take for all the water to be evaporated ?

Given :

An experiment is conducted using 4 L of water and ice made from 3 L of water.

Rate of evaporation of water =$\frac{7}{4} l/h$

Rate of melting of ice and thus producing water = $\frac{3}{2}$

To find:

We have to find the time taken for all the water to be evaporated.

Solution :

This implies,

Time taken for all the ice to melt $= \frac{3}{(\frac{3}{2})} hr = \frac{3}{3} \times 2 hr = 2 hours$.

The total amount of water $= 4+3 L = 7 L$

Time taken for all the water to evaporate $= \frac{7}{(\frac{7}{4})} hr = 7\times \frac{4}{7} hr = 4 hours$.

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Updated on: 10-Oct-2022

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