An elevator descends into mine shaft at the rate of 4m/min. If it begins to descends from 10 m above the ground. What will be its position after 1 hour ?

Given :

An elevator descends into mine shaft at the rate of 4m/min.

And, it begins to descends from 10 m above the ground.

To find :

We have to find the position of elevator after 1 hour.

Solution :

We know that,

$1 hour = 60 min$

The total distance it descends in $1 hour = 60 \times 4 m = 240 m$.

The final position of the elevator $= 240-10 m = 230 m$ below the ground.

So, the position of the elevator after 1 hour is 230 m below the ground.

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

413 Views

Kickstart Your Career

Get certified by completing the course

Get Started