An elevator descends into mine shaft at the rate of 4m/min. If it begins to descends from 10 m above the ground. What will be its position after 1 hour ?


Given :

An elevator descends into mine shaft at the rate of 4m/min.

And, it begins to descends from 10 m above the ground.


To find :

We have to find the position of elevator after 1 hour.


Solution :

  

We know that,

$1 hour = 60 min$

The total distance it descends in $1 hour = 60 \times 4 m = 240 m$.

The final position of the elevator $= 240-10 m = 230 m$ below the ground.


So, the position of the elevator after 1 hour is 230 m below the ground.

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Updated on: 10-Oct-2022

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