An electrical appliance has a resistance of $25 \Omega$. When this electrical appliance is connected to a $230 \mathrm{~V}$ supply line, the current passing through it will be:(a) $0.92 \mathrm{~A}$(b) $2.9 \mathrm{~A}$(c) $9.2 \mathrm{~A}$(d) $92 \mathrm{~A}$
Given:
Potential difference, V=230V
Resistance, R=25 ohms
To find:
Current, I
Solution:
According to the ohm's law:
$\mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}}$
$\mathrm{I}=\frac{\mathrm{230}}{\mathrm{25}}$
= 9.2 A
Answer is (c)
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