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An electric heater uses 600 kJ of electrical energy in 5 minutes. Calculate its power rating.
Energy used by electric heater $=600\ kJ=600\times10^3\ J$
Time $t=5\ minutes=5\times60\ s=300\ seconds$
Therefore, power $=\frac{energy\ used}{time}$
$=\frac{600\times10^3\ J}{300\ s}$
$=2\times10^3\ Watt$
$=2\ kW$ [As $1\ kilo-watt=10^3\ Watt$]
Therefore, the power rating of the heater is $2\ kWh$.
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