Add the following:$\frac{-2}{3}$ and $\frac{3}{4}$.

Given :

The given fractions are $\frac{-2}{3}$ and $\frac{3}{4}$.

To do :

We have to add the given fractions.

Solution :

LCM of denominators 3 and 4 $= 3\times 4 = 12$.

$\frac{12}{3} = 4$ and $\frac{12}{4} = 3$

$\frac{-2}{3} = \frac{(-2\times 4)}{(3\times 4)} = \frac{-8}{12}$

$\frac{3}{4} = \frac{(3\times 3)}{(4\times 3)} = \frac{9}{12}$

$\frac{-2}{3}  + \frac{3}{4}  =  \frac{-8}{12} + \frac{9}{12} = \frac{(-8+9)}{12} = \frac{1}{12}$.

Therefore, the sum of $\frac{-2}{3}$ and $\frac{3}{4}$ is $\frac{1}{12}$.

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Updated on: 10-Oct-2022

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