Add the following monomials:
(i) $ 8 x y, 2 x y, 9 x y $
$ \left(iv{}\right)-40 m n,-30 m n, 18 m n $

i) Given monomials are $8xy, 2xy$ and $9xy$.

To do: We have to find their sum. 

Solution: 

$8xy+2xy+9xy= xy(8+2+9)$

                            $=19xy$.

So, $8xy+2xy+9xy=19xy$

ii) Given monomials are $-40mn, -30mn$ and $18mn$.

To do: We have to find their sum. 

Solution:

$-40mn+(-30mn)+18mn=mn(-40-30+18)$

                                              $=(-70+18)mn$

                                               $=-52mn$

So, $-40mn+(-30mn)+18mn=-52mn$.

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Updated on: 10-Oct-2022

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