Add the following:
$l^{2}+m^{2}, m^{2}+n^{2}, n^{2}+l^{2}, 2lm+2mn+2nl$

Given:

$l^{2}+m^{2}, m^{2}+n^{2}, n^{2}+l^{2}, 2lm+2mn+2nl$

To do:

We have to add the above terms and simplify the expression. 

Solution:

We know that,

$(a+b)^2=a^2+2ab+b^2$

Therefore,

$l^{2}+m^{2}+m^{2}+n^{2}+n^{2}+l^{2}+2lm+2mn+2nl=(l^2+2lm+m^2)+(m^2+2mn+n^2)+(n^2+2ln+l^2)$

$=(l+m)^2+(m+n)^2+(n+l)^2$.

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Updated on: 10-Oct-2022

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