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Add the following:
$l^{2}+m^{2}, m^{2}+n^{2}, n^{2}+l^{2}, 2lm+2mn+2nl$
Given:
$l^{2}+m^{2}, m^{2}+n^{2}, n^{2}+l^{2}, 2lm+2mn+2nl$
To do:
We have to add the above terms and simplify the expression.
Solution:
We know that,
$(a+b)^2=a^2+2ab+b^2$
Therefore,
$l^{2}+m^{2}+m^{2}+n^{2}+n^{2}+l^{2}+2lm+2mn+2nl=(l^2+2lm+m^2)+(m^2+2mn+n^2)+(n^2+2ln+l^2)$
$=(l+m)^2+(m+n)^2+(n+l)^2$.
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