According to one of the Kepler's laws of planetary motion:

(a).\ r^2\propto T^3$
(b).\ r\propto T^2$
(c).\ r^3\propto T^2$
(d).\ r\propto \frac{1}{T^2}$


According to Kepler's law of planetary motion square of the time period $(T^2)$ is directly proportional to the cube of the semi-major axis$(r^3)$.

$T^2\propto r^3$

Or $r^3\propto T^2$

So, option (c) is correct.

Updated on: 10-Oct-2022

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