$ABCD$ is a square, $AC$ and $BD$ intersect at $O$. State the measure of $\angle AOB$.


Given:

$ABCD$ is a square, $AC$ and $BD$ intersect at $O$.

To do:

We have to determine the measure of $\angle AOB$.

Solution:

We know that,

Diagonals of a square bisect each other at right angles.


Therefore,

$\angle AOB = 90^o$.

The measure of $\angle AOB$ is $90^o$.

Tutorialspoint
Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

55 Views

Kickstart Your Career

Get certified by completing the course

Get Started
Advertisements