$ABCD$ is a rectangle with $\angle ABD = 40^o$. Determine $\angle DBC$.

Given:

$ABCD$ is a rectangle with $\angle ABD = 40^o$.

To do:

We have to determine $\angle DBC$.

Solution:

From the figure,

$\angle ABD + \angle DBC = 90^o$

$40^o + \angle DBC = 90^o$

$\angle DBC = 90^o - 40^o$

$\angle DBC = 50^o$

Hence, $\angle DBC = 50^o$.

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

96 Views

Kickstart Your Career

Get certified by completing the course

Get Started