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$ABCD$ is a rectangle. The diagonals $AC$ and $BD$ intersect each other at $O$. Find the value of $x$ if $OA=x+2$ and $OC=2x-1$.
Given: $ABCD$ is a rectangle. The diagonals $AC$ and $BD$ intersect each other at $O$ and $OA=x+2$ and $OC=2x-1$
To do: To find the value of $x$.
Solution:
$OA=OB$ [Diagonal bisect each other at the point $O$]
$\Rightarrow x+2=2x-1$
$\Rightarrow 2x-x=2+1$
$\Rightarrow x=3$
Updated on: 10-Oct-2022
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