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# A wire is bent to form a square of side 11 cm. If this wire is reshaped to form a rectangle of length 16 cm, find the breadth of the rectangle and area of the rectangle.

**Given:**

A wire is bent to form a square of side 11 cm.

The wire is reshaped to form a rectangle of length 16 cm.

**To do:**

We have to find the breadth and area of the rectangle.

**Solution:**

Side of square = 11 cm

Wire is reshaped from square to a rectangle.

So, Perimeter of square = Perimeter of rectangle

Perimeter of square = 4 $\times$ side

Perimeter of square = 4 $\times$ 11

Perimeter of square = 44 cm

So, Perimeter of rectangle = 44 cm

Length of rectangle = 16 cm

Perimeter of rectangle = 2 (length $+$ breadth)

44 = 2 (16 $+$ breadth)

$\frac{44}{2} = 16 +$ breadth

$22 = 16 +$ breadth

$22 - 16 =$ breadth

breadth = 6 cm

**The breadth of the rectangle is 6 cm.**

Area of rectangle = length $\times$ breadth

Area of rectangle = 16 $\times$ 6 cm^{2}

**The area of the rectangle is 96 sq.cm.
**