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A wire is bent to form a square of side 11 cm. If this wire is reshaped to form a rectangle of length 16 cm, find the breadth of the rectangle and area of the rectangle.
Given:
A wire is bent to form a square of side 11 cm.
The wire is reshaped to form a rectangle of length 16 cm.
To do:
We have to find the breadth and area of the rectangle.
Solution:
Side of square = 11 cm
Wire is reshaped from square to a rectangle.
So, Perimeter of square = Perimeter of rectangle
Perimeter of square = 4 $\times$ side
Perimeter of square = 4 $\times$ 11
Perimeter of square = 44 cm
So, Perimeter of rectangle = 44 cm
Length of rectangle = 16 cm
Perimeter of rectangle = 2 (length $+$ breadth)
44 = 2 (16 $+$ breadth)
$\frac{44}{2} = 16 +$ breadth
$22 = 16 +$ breadth
$22 - 16 =$ breadth
breadth = 6 cm
The breadth of the rectangle is 6 cm.
Area of rectangle = length $\times$ breadth
Area of rectangle = 16 $\times$ 6 cm2
The area of the rectangle is 96 sq.cm.